www.pudn.com > segment_ga.rar > cross.m

function c1=cross(s_code1) 
    
   %交叉算子 
   
   pc=0.8;       %交叉概率取0.6 
   population=10; 
    
   %(1,2)/(3,4)/(5,6)进行交叉运算，(7,8)/(9,10)复制 
    
   ww=s_code1; 
    
   for i=1:(pc*population/2) 
       r=abs(round(rand(1)*10)-3); 
       for j=(r+1):8 
           temp=ww(2*i-1,j); 
           ww(2*i-1,j)=ww(2*i,j); 
           ww(2*i,j)=temp; 
       end 
   end 
    
   c1=ww;